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The real image of the object is asked Aug 3, 2019 in Physics by Nisub ( 71.0k points) A lens producing more converging or more diverging, is said to have more power. When a lens of known focal length, f is used to find the relationship between the object distance. Object distance (u) equals image distance (v). The image distance, v is measured and recorded. An object is placed at a distance u cm from a concave mirror of focal length f cm. What is an electric field and how is it created? An object of height 6 cm is placed at a distance of 20 cm from a concave lens. Damped Oscillations, Forced Oscillations and Resonance. The mean value for (1/u + 1/v) is determined. Relationship between Energy Transferred, Current, Voltage and Time. The mirror equation gives us- v 1 + u 1 = f 1 Where, u = Object Distance v = Image Distance f = Focal Length. Aim: To find the relationship between the object distance, u, image distance, v and the focal length, f of a lens. • Apparatus: Light bulb, convex lens (f = 15 cm), metre rule, white screen, lens holder Method: Conclusion: The relationship between the object distance, u, image distance, v and focal length, f of a lens is, Filed Under: Physics Tagged With: Lens Formula, Lens Formula & Magnification – Lens Power, Lens Power, Linear Magnification, Numerical Methods In Lens, Power Of Lens, ICSE Previous Year Question Papers Class 10, Image Formation By Concave And Convex Lenses, To Construct Optical Devices Using Lenses, Lens Formula & Magnification – Lens Power, Concise Mathematics Class 10 ICSE Solutions, Concise Chemistry Class 10 ICSE Solutions, Concise Mathematics Class 9 ICSE Solutions. The graph between object distance u and image distance v for a lens is given below. The focal length, f of the convex lens used in the activity is given as 15 cm. Step 2 is repeated for object distances, u = 35 cm, 30 cm, 25 cm, 20 cm and 18 cm. Question 1 The equation connecting object distance, u, image distance, v and focal length, f, for a thin lens is 111 a) With the magnitude of the magnification, m, defined in terms of u and v, show that by rearranging the equation given above, the plot of m against v will give a straight line graph. If a graph of 1/v against 1/u is plotted, the graph is as shown in Figure. Its focal length is 10 cm. All distances are measured from the optical centre of the lens. Your IP: 132.148.159.163 The bulb is switched on and the screen is moved backward and forward to get a sharp image formed on it. From the graph, Conclusion: The relationship between the object distance, u, image distance, v and focal length, f of a lens is For an appropriate object distance u, find the image distance v.Measure u and v.; Repeat above step at few more object distances. See more. By placing a convex lens at a distance of 3 2 c m from the object, it is found that a distinct image of the object is formed on the screen. The results are tabulated in Table. The graph is a straight line graph cutting the two axes at two intercepts. The values of the intercepts are both equal to 0.067. The focal length of the lens used, f = 15 cm. An object is placed at distance of 6 4 c m from a white screen. Another way to prevent getting this page in the future is to use Privacy Pass. A short linear object of length l lies along the axis of a concave mirror of focal length f at a distance u asked Sep 20, 2019 in Physics by SudhirMandal ( 53.5k points) ray optics If you are at an office or shared network, you can ask the network administrator to run a scan across the network looking for misconfigured or infected devices. The focal length of the lens is (A) 5± 0.1 (B) 5± 0.05 (C) 0.5± The value of 1/f is determined. The convex lens is moved to a position where the object distance, u = 40 cm. How do you calculate the total resistance of a series circuit? Get the focal length from all measurements by (a) taking average of calculated f or (b) from u versus v graph or (c) from versus graph. u v h i h o 1.2 REFLECTION & REFRACTION Images The magnification , m, of an image is defined as: 16 1.2 REFLECTION & REFRACTION If m is negative, the image is inverted (upside down). If you are on a personal connection, like at home, you can run an anti-virus scan on your device to make sure it is not infected with malware. The size of an image formed by a lens varies with the position of the object. You may need to download version 2.0 now from the Chrome Web Store. The light bulb is kept at a fixed position at one end of the metre rule. The values of 1/u, 1/v and (1/u + 1/v) are calculated and corrected to two significant figures. Object distance definition, the distance between the lens of a camera and an object being photographed. How do you calculate the total resistance of a parallel circuit? The apparatus is set up as shown in figure. • Performance & security by Cloudflare, Please complete the security check to access. Completing the CAPTCHA proves you are a human and gives you temporary access to the web property. The power for a convex lens is positive and the power for a concave lens is negative. The ratio of the image size to the object size is the same as the ratio of the image distance to the object distance. If a graph of 1/v against 1/u is plotted, the graph is as shown in Figure. Definition: The ratio of the size of the image formed by refraction from the lens to the size of the object, is called linear magnification produced by the lens. Find the position and size of the image. Now according to the sign convention, distances measured in the left direction of the mirror will be taken as -ve; while that on the right will be +ve. Figure shows a graph of v against magnification, m for a lens experiment. It is represented by the symbol m. Definition: It is the capacity or the ability of a lens to deviate (converge or diverge) the path of rays passing through it. What is the Relationship between Electric Current and Potential Difference? The lens formula may be applied to convex lenses as well as concave lenses provided the ‘real is positive’ sign convention is followed. What are the characteristics of the image formed if the object distance is 15 cm? The height of the object, ho is 5 cm. What is alternating current and direct current? Table shows the sign convention for the values of object distance, image distance and focal length. The power of a lens is related to its focal length, f by the equation: The shorter the focal length, the greater the power. This ratio is the. The simplest way to compare the image with the object is by the ratio of their sizes. Cloudflare Ray ID: 5f8ef3830ef00503 The values of the intercepts are both equal to 0.067. An object is placed in front of a convex lens with a focal length, f of 10 cm. The u-v method to find focal length of a given concave mirror or convex lens consists of following steps . The graph is a straight line graph cutting the two axes at two intercepts. All the corresponding values of the image distance, v are measured and recorded. What is magnetic force on a current carrying conductor? Figure shows the position of an image, I of an object, O formed by a convex lens.